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Analyze Factorial DesignTwo-Level Factorial Designs |
Use the p-values (P) in the analysis of variance table to determine which of the effects in the model are statistically significant. Typically, you look at the interaction effects in the model first, because a significant interaction will influence how you interpret the main effects. To use the p-value, you need to do the following:
- If the p-value is less than or equal to a, conclude that the effect is significant.
- If the p-value is greater than a, conclude that the effect is not significant.
In theory, any VIF value greater than 1 can inflate the variance of the coefficients so much that statistical significance is a less useful way to identify candidate models. In practice, values greater than 5–10 can produce unstable coefficients that are difficult to interpret and, thereby, prompt corrective measures
Example Output |
Analysis of Variance
Source DF Adj SS Adj MS F-Value P-Value Model 11 451.357 41.032 17.99 0.007 Covariates 1 3.591 3.591 1.58 0.278 MeasTemp 1 3.591 3.591 1.58 0.278 Linear 4 304.587 76.147 33.39 0.002 Material 1 35.053 35.053 15.37 0.017 InjPress 1 113.068 113.068 49.59 0.002 InjTemp 1 75.533 75.533 33.12 0.005 CoolTemp 1 38.666 38.666 16.96 0.015 2-Way Interactions 6 20.309 3.385 1.48 0.366 Material*InjPress 1 1.732 1.732 0.76 0.433 Material*InjTemp 1 3.045 3.045 1.34 0.312 Material*CoolTemp 1 0.095 0.095 0.04 0.848 InjPress*InjTemp 1 1.538 1.538 0.67 0.458 InjPress*CoolTemp 1 0.012 0.012 0.01 0.947 InjTemp*CoolTemp 1 14.694 14.694 6.44 0.064 Error 4 9.121 2.280 Total 15 460.478 |
Interpretation |
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For the insulation data, the analysis of variance table shows the following results:
The p-value of 0.366 for the set of two-way interactions is not less than 0.05. Therefore, the group of two-way interactions is not significant. The p-value for the interaction between the injection temperature and the cooling temperature is 0.064, which is not less than 0.05. However, this interaction is statistically significant in some alternative models. For example, the model that contains the main effects, the covariate, and only this two-way interaction.
The p-value of 0.002 for the set of main effects is less than 0.05. Therefore, there is significant evidence that at least one factor has an effect on insulation strength. All the p-values for the individual main effects are less than 0.05. Material type (p-value = 0.017), injection pressure (p-value = 0.002), injection temperature (p-value = 0.005), and cooling temperature (p-value = 0.015) all have a significant effect on insulation strength.