noco_e044 发表于 2025-6-16 14:51:50

AIAG & VDA FMEA(2019版),措施優先級(AP) Excel 3種函數公式

感謝qlong之分享啟發,針對措施優先級(AP)的Excel函數計算,再分享3種寫法給大家參考。

AIAG & VDA FMEA中AP的公式
https://www.pinzhi.org/thread-90445-1-1.html

措施優先級(AP)表,摘錄自 BSI 對於新版FMEA所應有的認知
https://www.bsigroup.com/localfiles/zh-tw/e-news/no191/knowledge-of-the-new-fmea-randy-chiang.pdf

新人發表學習見解,如對各位大大有所幫助,懇請回帖鼓勵,歡迎不吝指導。
第一種 寫法 IFS 列舉法
第二種 寫法 巢狀IF列舉法
第三種 寫法 SWITCH(TRUE…)+巢狀 IF

第一種 (利用 X<=AP 且 AP<= Y 方式撰寫,更易理解)


=IFERROR(IFS(
   AND(9<=A3,A3<=10,6<=B3,B3<=10,1<=C3,C3<=10),"H",
   AND(9<=A3,A3<=10,4<=B3,B3<=5,2<=C3,C3<=10),"H",
    AND(9<=A3,A3<=10,4<=B3,B3<=5,1<=C3,C3<=1),"M",
   AND(9<=A3,A3<=10,2<=B3,B3<=3,7<=C3,C3<=10),"H",
   AND(9<=A3,A3<=10,2<=B3,B3<=3,5<=C3,C3<=6),"M",
    AND(9<=A3,A3<=10,2<=B3,B3<=3,1<=C3,C3<=4),"L",
   AND(9<=A3,A3<=10,1<=B3,B3<=1,1<=C3,C3<=10),"L",
   AND(7<=A3,A3<=8,8<=B3,B3<=10,1<=C3,C3<=10),"H",
    AND(7<=A3,A3<=8,6<=B3,B3<=7,2<=C3,C3<=10),"H",
   AND(7<=A3,A3<=8,6<=B3,B3<=7,1<=C3,C3<=1),"M",
   AND(7<=A3,A3<=8,4<=B3,B3<=5,7<=C3,C3<=10),"M",
   AND(7<=A3,A3<=8,4<=B3,B3<=5,1<=C3,C3<=6),"M",
    AND(7<=A3,A3<=8,2<=B3,B3<=3,5<=C3,C3<=10),"M",
   AND(7<=A3,A3<=8,2<=B3,B3<=3,1<=C3,C3<=4),"L",
   AND(7<=A3,A3<=8,1<=B3,B3<=1,1<=C3,C3<=10),"L",
    AND(4<=A3,A3<=6,8<=B3,B3<=10,5<=C3,C3<=10),"H",
   AND(4<=A3,A3<=6,8<=B3,B3<=10,1<=C3,C3<=4),"M",
   AND(4<=A3,A3<=6,6<=B3,B3<=7,2<=C3,C3<=10),"M",
    AND(4<=A3,A3<=6,6<=B3,B3<=7,1<=C3,C3<=1),"L",
   AND(4<=A3,A3<=6,4<=B3,B3<=5,7<=C3,C3<=10),"M",
   AND(4<=A3,A3<=6,4<=B3,B3<=5,1<=C3,C3<=6),"L",
    AND(4<=A3,A3<=6,1<=B3,B3<=3,1<=C3,C3<=10),"L",
   AND(2<=A3,A3<=3,8<=B3,B3<=10,5<=C3,C3<=10),"M",
   AND(2<=A3,A3<=3,8<=B3,B3<=10,1<=C3,C3<=4),"L",
    AND(2<=A3,A3<=3,1<=B3,B3<=7,1<=C3,C3<=10),"L",
   AND(1<=A3,A3<=1,1<=B3,B3<=10,1<=C3,C3<=10),"L"
    ),"")


第二種 利用 巢式IF 逐層判斷

=IFERROR(
      IF(A3>=9,
         IF(B3>=6,"H",
            IF(B3>=4,IF(C3>=2,"H","M"),
            IF(B3>=2,IF(C3>=7,"H",IF(C3>=5,"M","L")),"L")
         )
         ),
      IF(A3>=7,
         IF(B3>=8,"H",
            IF(B3>=6,IF(C3>=2,"H","M"),
            IF(B3>=4,"M",
                IF(B3>=2,IF(C3>=5,"M","L"),"L")
             )
         )
         ),
      IF(A3>=4,
         IF(B3>=8,IF(C3>=5,"H","M"),
            IF(B3>=6,IF(C3>=2,"M","L"),
            IF(B3>=4,IF(C3>=7,"M","L"),"L")
         )
         ),
      IF(A3>=2,
         IF(B3>=8,IF(C3>=5,"M","L"),"L"),
      "L"
      )))),
    "")


第三種 利用 SWITCH(TRUE…)+巢狀 IF (簡潔清楚)

=IFERROR(
      SWITCH(TRUE,
      A3>=9,   IF(B3>=6,"H",IF(B3>=4,IF(C3>=2,"H","M"),IF(B3>=2,IF(C3>=7,"H",IF(C3>=5,"M","L")),"L"))),
      A3>=7,   IF(B3>=8,"H",IF(B3>=6,IF(C3>=2,"H","M"),IF(B3>=4,"M",IF(B3>=2,IF(C3>=5,"M","L"),"L")))),
      A3>=4,IF(B3>=8,IF(C3>=5,"H","M"),IF(B3>=6,IF(C3>=2,"M","L"),IF(B3>=4,IF(C3>=7,"M","L"),"L"))),
      A3>=2,IF(B3>=8,IF(C3>=5,"M","L"),"L"),
      TRUE,   "L"
      ),
    "")

asdqwe123 发表于 2025-6-16 21:30:03

谢谢分享

samtang 发表于 2025-6-17 05:25:48

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xiang129 发表于 2025-6-17 05:35:30


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comp88 发表于 2025-6-17 05:56:41

{:1_180:}

strong_909 发表于 2025-6-17 07:12:13


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tianzs 发表于 2025-6-17 07:43:56


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510389 发表于 2025-6-17 07:53:52

{:1_180:}{:1_180:}{:1_180:}

yxp8012 发表于 2025-6-17 08:02:57


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有缘结识品质 发表于 2025-6-17 08:05:12

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