Example of 1 Proportionmain topic interpreting results session command see also
Example of 1 ProportionA county district attorney would like to run for the office of state district attorney. She has decided that she will give up her county office and run for state office if more than 65% of her party constituents support her. You need to test H0: p = .65 versus H1: p > .65.
As her campaign manager, you collected data on 950 randomly selected party members and find that 560 party members support the candidate. A test of proportion was performed to determine whether or not the proportion of supporters was greater than the required proportion of 0.65. In addition, a 95% confidence bound was constructed to determine the lower bound for the proportion of supporters.
1 Choose Stat > Basic Statistics > 1 Proportion.
2 Choose Summarized data.
3 In Number of events, enter 560. In Number of trials, enter 950.
4 Check Perform hypothesis test. In Hypothesized proportion, enter 0.65.
5 Click Options. Under Alternative hypothesis, choose Proportion > hypothesized proportion. Click OK in each dialog box.
Session window output
Test and CI for One Proportion
Test of p = 0.65 vs p > 0.65
Exact Sample X N Sample p 95% Lower Bound P-Value 1 560 950 0.589474 0.562515 1.000 |
The p-value of 1.0 suggests that the data are consistent with the null hypothesis (H0: p = 0.65), that is, the proportion of party members that support the candidate is not greater than the required proportion of 0.65. As her campaign manager, you would advise her not to run for the office of state district attorney.