各位老师帮忙解决一下：NDC怎么调整大于5

iweihai

APPRAISER/		PART										AVERAGE					Measurement Unit Analysis				% Total Variation (TV)
TRIAL #		1	2	3	4	5	6	7	8	9	10			Repeatability - Equipment Variation (EV)
1.  A	1	5.165	5.166	5.165	5.167	5.166	5.165	5.166	5.167	5.166	5.165		5.166	EV	=	R  x  K1			Trials	K1	% EV	=	100 (EV/TV)
2.	2	5.166	5.165	5.167	5.166	5.165	5.166	5.167	5.165	5.167	5.166		5.166		=	0.002 x 0.5908			2	0.8862		=	100(0.001/0.001)
3.	3	5.165	5.167	5.165	5.166	5.167	5.165	5.165	5.166	5.165	5.166		5.166		=	0.001			3	0.5908		=	98.77
4.	AVE	5.165	5.166	5.166	5.166	5.166	5.165	5.166	5.166	5.166	5.166	xa=	5.166	Reproducibility - Appraiser Variation (AV)
5.	R	0.001	0.002	0.002	0.001	0.002	0.001	0.002	0.002	0.002	0.001	ra=	0.002	AV	=	{(xDIFF x K2)2 - (EV2/nr)}1/2					% AV	=	100 (AV/TV)
6.  B	1	5.166	5.167	5.167	5.166	5.167	5.166	5.165	5.166	5.165	5.166		5.166		=	{(0.00 x 0.5231)^2 - (0.00 ^2/(10 x 3))}^1/2						=	100(0.000/0.001)
7.	2	5.165	5.166	5.167	5.166	5.168	5.165	5.165	5.167	5.164	5.165		5.166		=	0.000						=	4.59
8.	3	5.167	5.166	5.165	5.167	5.165	5.166	5.167	5.166	5.166	5.167		5.166					Appraisers	2	3
9.	AVE	5.166	5.166	5.166	5.166	5.167	5.166	5.166	5.166	5.165	5.166	xb=	5.166	n = parts        r = trials				K2	0.7071	0.5231
10.	R	0.002	0.001	0.002	0.001	0.003	0.001	0.002	0.001	0.002	0.002	rb=	0.002	Repeatability & Reproducibility (GRR)							% GRR	=	100 (GRR/TV)
11.  C	1	5.166	5.166	5.165	5.166	5.165	5.167	5.166	5.165	5.165	5.166		5.166	GRR	=	{(EV2 + AV2)}1/2			Parts	K3		=	100(0.001/0.001)
12.	2	5.165	5.165	5.166	5.165	5.165	5.166	5.165	5.166	5.167	5.166		5.166		=	{(0.001^2 + 0.000^2)}^1/2			2	0.7071		=	98.88
13.	3	5.166	5.166	5.167	5.165	5.166	5.165	5.167	5.166	5.165	5.165		5.166		=	0.001			3	0.5231	Gage system needs improvement
14.	AVE	5.166	5.166	5.166	5.165	5.165	5.166	5.166	5.166	5.166	5.166	xc=	5.166	Part Variation (PV)					4	0.4467
15.	R	0.001	0.001	0.002	0.001	0.001	0.002	0.002	0.001	0.002	0.001	rc=	0.001	PV	=	RP x K3			5	0.4030	% PV	=	100 (PV/TV)
16. PART												X=	5.166		=	0.000 x 0.3146			6	0.3742		=	100(0.000/0.001)
AVERAGE		5.166	5.166	5.166	5.166	5.166	5.166	5.166	5.166	5.166	5.166	Rp=	0.000		=	0.000			7	0.3534		=	14.92
17.	(ra + rb + rc) / (# OF APPRAISERS) =											R=	0.002	Total Variation (TV)					8	0.3375
18.	xDIFF = (Max x - Min x) =											xDIFF=	0.000	TV	=	{(GRR2 + PV2)}1/2			9	0.3249	ndc	=	1.41(PV/GRR)
19.	* UCLR = R x D4 =											UCLR=	0.004		=	{(0.001^2 + 0.000^2)}^1/2			10	0.3146		=	1.41(0.000/0.001)
															=	0.001						=	0
* D4 =3.27 for 2 trials and 2.58 for 3 trials.  UCLR represents the limit of individual R's.  Circle those that are																					Gage discrimination low
beyond this limit.  Identify the cause and correct.  Repeat these readings using the same appraiser and unit as originally used or
discard values and re-average and recompute R and the limiting value from the remaining observations.														For information on the theory and constants used in the form see MSA Reference Manual, Fourth edition.

samisok

调整取样范围，包含公差带的上中下限取样

tfan

samisok 发表于 2021-12-6 16:04
调整取样范围，包含公差带的上中下限取样

zhangbolun

flyerchang

你重复数太多了

532128wang

调整测试值的上下限，减少产品变差

kzt1986

建议先了解NDC的含义，NDC大于5代表什么意思，有什么作用

393690473

kzt1986 发表于 2025-3-7 16:17
建议先了解NDC的含义，NDC大于5代表什么意思，有什么作用

DC大于5代表什么意思，有什么作用，我也想知道，赐教一下

kzt1986

393690473 发表于 2025-9-12 12:31
DC大于5代表什么意思，有什么作用，我也想知道，赐教一下

代表数据分层，层级太少体现不出测量系统的区分度

神仙命长

NDC ＜5，代表现有的量具相对于现有过程能力分辨率不足，现在的测量系统不能评价现在的生产过程能力。你这个要么过程太过稳定需要换更精确量具，要么就是取样有问题，样品没有覆盖整个过程的变差。